6(s+4)=3s+27

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Solution for 6(s+4)=3s+27 equation: 



6(s+4)=3s+27

We move all terms to the left:

6(s+4)-(3s+27)=0

We multiply parentheses

6s-(3s+27)+24=0

We get rid of parentheses

6s-3s-27+24=0

We add all the numbers together, and all the variables

3s-3=0

We move all terms containing s to the left, all other terms to the right

3s=3

s=3/3

s=1

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