6(t+2)-3(t-4)=6(t-7)+8

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Solution for 6(t+2)-3(t-4)=6(t-7)+8 equation:


6 (t+2)-3 (t-4)=6 (t-7)+8

We simplify the equation to the form, which is simple to understand
6(t+2)-3(t-4)=6(t-7)+8

Reorder the terms in parentheses
+(+6t+12)-3*(t-4)=6*(t-7)+8

Remove unnecessary parentheses
+6t+12-3+*(+t-4+)=+6+*(+t-7+)+8

Reorder the terms in parentheses
+6t+12+(-3t+12)=6*(t-7)+8

Remove unnecessary parentheses
+6t+12-3t+12=+6+*(+t-7+)+8

Reorder the terms in parentheses
+6t+12-3t+12=+(+6t-42)+8

Remove unnecessary parentheses
+6t+12-3t+12=+6t-42+8

We move all terms containing t to the left and all other terms to the right.
+6t-3t-6t=-42+8-12-12

We simplify left and right side of the equation.
-3t=-58

We divide both sides of the equation by -3 to get t.
t=19.333333333333

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