6(t+2)=2(t-2)

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Solution for 6(t+2)=2(t-2) equation: 



6(t+2)=2(t-2)

We move all terms to the left:

6(t+2)-(2(t-2))=0

We multiply parentheses

6t-(2(t-2))+12=0



We calculate terms in parentheses: -(2(t-2)), so:

2(t-2)

We multiply parentheses

2t-4

Back to the equation:

-(2t-4)



We get rid of parentheses

6t-2t+4+12=0

We add all the numbers together, and all the variables

4t+16=0

We move all terms containing t to the left, all other terms to the right

4t=-16

t=-16/4

t=-4

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