6(t+2)=2t+28

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Solution for 6(t+2)=2t+28 equation: 



6(t+2)=2t+28

We move all terms to the left:

6(t+2)-(2t+28)=0

We multiply parentheses

6t-(2t+28)+12=0

We get rid of parentheses

6t-2t-28+12=0

We add all the numbers together, and all the variables

4t-16=0

We move all terms containing t to the left, all other terms to the right

4t=16

t=16/4

t=4

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