6(t-1)-7=4(t+2)+1

Solution for 6(t-1)-7=4(t+2)+1 equation:

6(t-1)-7=4(t+2)+1

We move all terms to the left:

6(t-1)-7-(4(t+2)+1)=0

We multiply parentheses

6t-(4(t+2)+1)-6-7=0


We calculate terms in parentheses: -(4(t+2)+1), so:

4(t+2)+1

We multiply parentheses

4t+8+1

We add all the numbers together, and all the variables

4t+9

Back to the equation:

-(4t+9)


We add all the numbers together, and all the variables

6t-(4t+9)-13=0

We get rid of parentheses

6t-4t-9-13=0

We add all the numbers together, and all the variables

2t-22=0

We move all terms containing t to the left, all other terms to the right

2t=22

t=22/2

t=11