6(t-14)+2(t-3)=14

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Solution for 6(t-14)+2(t-3)=14 equation: 



6(t-14)+2(t-3)=14

We move all terms to the left:

6(t-14)+2(t-3)-(14)=0

We multiply parentheses

6t+2t-84-6-14=0

We add all the numbers together, and all the variables

8t-104=0

We move all terms containing t to the left, all other terms to the right

8t=104

t=104/8

t=13

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