6(t-2)+4t=5(2t+4)-11

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Solution for 6(t-2)+4t=5(2t+4)-11 equation: 



6(t-2)+4t=5(2t+4)-11

We move all terms to the left:

6(t-2)+4t-(5(2t+4)-11)=0

We add all the numbers together, and all the variables

4t+6(t-2)-(5(2t+4)-11)=0

We multiply parentheses

4t+6t-(5(2t+4)-11)-12=0



We calculate terms in parentheses: -(5(2t+4)-11), so:

5(2t+4)-11

We multiply parentheses

10t+20-11

We add all the numbers together, and all the variables

10t+9

Back to the equation:

-(10t+9)



We add all the numbers together, and all the variables

10t-(10t+9)-12=0

We get rid of parentheses

10t-10t-9-12=0

We add all the numbers together, and all the variables

-21!=0

There is no solution for this equation

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