6(t-3)+4t=5(2t+2)-9

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Solution for 6(t-3)+4t=5(2t+2)-9 equation:


Simplifying
6(t + -3) + 4t = 5(2t + 2) + -9

Reorder the terms:
6(-3 + t) + 4t = 5(2t + 2) + -9
(-3 * 6 + t * 6) + 4t = 5(2t + 2) + -9
(-18 + 6t) + 4t = 5(2t + 2) + -9

Combine like terms: 6t + 4t = 10t
-18 + 10t = 5(2t + 2) + -9

Reorder the terms:
-18 + 10t = 5(2 + 2t) + -9
-18 + 10t = (2 * 5 + 2t * 5) + -9
-18 + 10t = (10 + 10t) + -9

Reorder the terms:
-18 + 10t = 10 + -9 + 10t

Combine like terms: 10 + -9 = 1
-18 + 10t = 1 + 10t

Add '-10t' to each side of the equation.
-18 + 10t + -10t = 1 + 10t + -10t

Combine like terms: 10t + -10t = 0
-18 + 0 = 1 + 10t + -10t
-18 = 1 + 10t + -10t

Combine like terms: 10t + -10t = 0
-18 = 1 + 0
-18 = 1

Solving
-18 = 1

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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