6(t-3)+8t=7(2t+2)-8

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Solution for 6(t-3)+8t=7(2t+2)-8 equation: 



6(t-3)+8t=7(2t+2)-8

We move all terms to the left:

6(t-3)+8t-(7(2t+2)-8)=0

We add all the numbers together, and all the variables

8t+6(t-3)-(7(2t+2)-8)=0

We multiply parentheses

8t+6t-(7(2t+2)-8)-18=0



We calculate terms in parentheses: -(7(2t+2)-8), so:

7(2t+2)-8

We multiply parentheses

14t+14-8

We add all the numbers together, and all the variables

14t+6

Back to the equation:

-(14t+6)



We add all the numbers together, and all the variables

14t-(14t+6)-18=0

We get rid of parentheses

14t-14t-6-18=0

We add all the numbers together, and all the variables

-24!=0

There is no solution for this equation

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