6(t-3)+8t=7(2t+3)-11

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Solution for 6(t-3)+8t=7(2t+3)-11 equation: 



6(t-3)+8t=7(2t+3)-11

We move all terms to the left:

6(t-3)+8t-(7(2t+3)-11)=0

We add all the numbers together, and all the variables

8t+6(t-3)-(7(2t+3)-11)=0

We multiply parentheses

8t+6t-(7(2t+3)-11)-18=0



We calculate terms in parentheses: -(7(2t+3)-11), so:

7(2t+3)-11

We multiply parentheses

14t+21-11

We add all the numbers together, and all the variables

14t+10

Back to the equation:

-(14t+10)



We add all the numbers together, and all the variables

14t-(14t+10)-18=0

We get rid of parentheses

14t-14t-10-18=0

We add all the numbers together, and all the variables

-28!=0

There is no solution for this equation

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