6(t-3)=2(2-2t)

Solution for 6(t-3)=2(2-2t) equation:

6(t-3)=2(2-2t)

We move all terms to the left:

6(t-3)-(2(2-2t))=0

We add all the numbers together, and all the variables

6(t-3)-(2(-2t+2))=0

We multiply parentheses

6t-(2(-2t+2))-18=0


We calculate terms in parentheses: -(2(-2t+2)), so:

2(-2t+2)

We multiply parentheses

-4t+4

Back to the equation:

-(-4t+4)


We get rid of parentheses

6t+4t-4-18=0

We add all the numbers together, and all the variables

10t-22=0

We move all terms containing t to the left, all other terms to the right

10t=22

t=22/10

t=2+1/5