6(t-3)=2(9-2t)T=

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Solution for 6(t-3)=2(9-2t)T= equation:



6(t-3)=2(9-2t)=
We move all terms to the left:
6(t-3)-(2(9-2t))=0
We add all the numbers together, and all the variables
6(t-3)-(2(-2t+9))=0
We multiply parentheses
6t-(2(-2t+9))-18=0
We calculate terms in parentheses: -(2(-2t+9)), so:
2(-2t+9)
We multiply parentheses
-4t+18
Back to the equation:
-(-4t+18)
We get rid of parentheses
6t+4t-18-18=0
We add all the numbers together, and all the variables
10t-36=0
We move all terms containing t to the left, all other terms to the right
10t=36
t=36/10
t=3+3/5

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