6(t-4)+7t=2

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Solution for 6(t-4)+7t=2 equation: 



6(t-4)+7t=2

We move all terms to the left:

6(t-4)+7t-(2)=0

We add all the numbers together, and all the variables

7t+6(t-4)-2=0

We multiply parentheses

7t+6t-24-2=0

We add all the numbers together, and all the variables

13t-26=0

We move all terms containing t to the left, all other terms to the right

13t=26

t=26/13

t=2

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