6(t-4)+8t=7(2t+3)-8

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Solution for 6(t-4)+8t=7(2t+3)-8 equation: 



6(t-4)+8t=7(2t+3)-8

We move all terms to the left:

6(t-4)+8t-(7(2t+3)-8)=0

We add all the numbers together, and all the variables

8t+6(t-4)-(7(2t+3)-8)=0

We multiply parentheses

8t+6t-(7(2t+3)-8)-24=0



We calculate terms in parentheses: -(7(2t+3)-8), so:

7(2t+3)-8

We multiply parentheses

14t+21-8

We add all the numbers together, and all the variables

14t+13

Back to the equation:

-(14t+13)



We add all the numbers together, and all the variables

14t-(14t+13)-24=0

We get rid of parentheses

14t-14t-13-24=0

We add all the numbers together, and all the variables

-37!=0

There is no solution for this equation

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