6(t-4)+8t=7(2t+5)-13

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Solution for 6(t-4)+8t=7(2t+5)-13 equation: 



6(t-4)+8t=7(2t+5)-13

We move all terms to the left:

6(t-4)+8t-(7(2t+5)-13)=0

We add all the numbers together, and all the variables

8t+6(t-4)-(7(2t+5)-13)=0

We multiply parentheses

8t+6t-(7(2t+5)-13)-24=0



We calculate terms in parentheses: -(7(2t+5)-13), so:

7(2t+5)-13

We multiply parentheses

14t+35-13

We add all the numbers together, and all the variables

14t+22

Back to the equation:

-(14t+22)



We add all the numbers together, and all the variables

14t-(14t+22)-24=0

We get rid of parentheses

14t-14t-22-24=0

We add all the numbers together, and all the variables

-46!=0

There is no solution for this equation

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