6(t-4)=2(t+3)

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Solution for 6(t-4)=2(t+3) equation: 



6(t-4)=2(t+3)

We move all terms to the left:

6(t-4)-(2(t+3))=0

We multiply parentheses

6t-(2(t+3))-24=0



We calculate terms in parentheses: -(2(t+3)), so:

2(t+3)

We multiply parentheses

2t+6

Back to the equation:

-(2t+6)



We get rid of parentheses

6t-2t-6-24=0

We add all the numbers together, and all the variables

4t-30=0

We move all terms containing t to the left, all other terms to the right

4t=30

t=30/4

t=7+1/2

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