6(u+1)-10=4(I-1)+2u

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Solution for 6(u+1)-10=4(I-1)+2u equation: 



6(u+1)-10=4(-1)+2u

We move all terms to the left:

6(u+1)-10-(4(-1)+2u)=0

We multiply parentheses

6u-(4(-1)+2u)+6-10=0



We calculate terms in parentheses: -(4(-1)+2u), so:

4(-1)+2u

determiningTheFunctionDomain
2u+4(-1)

We add all the numbers together, and all the variables

2u-4

Back to the equation:

-(2u-4)



We add all the numbers together, and all the variables

6u-(2u-4)-4=0

We get rid of parentheses

6u-2u+4-4=0

We add all the numbers together, and all the variables

4u=0

u=0/4

u=0

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