6(u+2)+1=2(3u-5)

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Solution for 6(u+2)+1=2(3u-5) equation:


Simplifying
6(u + 2) + 1 = 2(3u + -5)

Reorder the terms:
6(2 + u) + 1 = 2(3u + -5)
(2 * 6 + u * 6) + 1 = 2(3u + -5)
(12 + 6u) + 1 = 2(3u + -5)

Reorder the terms:
12 + 1 + 6u = 2(3u + -5)

Combine like terms: 12 + 1 = 13
13 + 6u = 2(3u + -5)

Reorder the terms:
13 + 6u = 2(-5 + 3u)
13 + 6u = (-5 * 2 + 3u * 2)
13 + 6u = (-10 + 6u)

Add '-6u' to each side of the equation.
13 + 6u + -6u = -10 + 6u + -6u

Combine like terms: 6u + -6u = 0
13 + 0 = -10 + 6u + -6u
13 = -10 + 6u + -6u

Combine like terms: 6u + -6u = 0
13 = -10 + 0
13 = -10

Solving
13 = -10

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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