6(u+2)=-3(3u-3)+3u

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Solution for 6(u+2)=-3(3u-3)+3u equation: 



6(u+2)=-3(3u-3)+3u

We move all terms to the left:

6(u+2)-(-3(3u-3)+3u)=0

We multiply parentheses

6u-(-3(3u-3)+3u)+12=0



We calculate terms in parentheses: -(-3(3u-3)+3u), so:

-3(3u-3)+3u

We add all the numbers together, and all the variables

3u-3(3u-3)

We multiply parentheses

3u-9u+9

We add all the numbers together, and all the variables

-6u+9

Back to the equation:

-(-6u+9)



We get rid of parentheses

6u+6u-9+12=0

We add all the numbers together, and all the variables

12u+3=0

We move all terms containing u to the left, all other terms to the right

12u=-3

u=-3/12

u=-1/4

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