6(u+2)=-6u+48

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Solution for 6(u+2)=-6u+48 equation: 



6(u+2)=-6u+48

We move all terms to the left:

6(u+2)-(-6u+48)=0

We multiply parentheses

6u-(-6u+48)+12=0

We get rid of parentheses

6u+6u-48+12=0

We add all the numbers together, and all the variables

12u-36=0

We move all terms containing u to the left, all other terms to the right

12u=36

u=36/12

u=3

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