6(u+2)=8u-4

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Solution for 6(u+2)=8u-4 equation: 



6(u+2)=8u-4

We move all terms to the left:

6(u+2)-(8u-4)=0

We multiply parentheses

6u-(8u-4)+12=0

We get rid of parentheses

6u-8u+4+12=0

We add all the numbers together, and all the variables

-2u+16=0

We move all terms containing u to the left, all other terms to the right

-2u=-16

u=-16/-2

u=+8

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