6(u+3)=-3u+27

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Solution for 6(u+3)=-3u+27 equation:



6(u+3)=-3u+27
We move all terms to the left:
6(u+3)-(-3u+27)=0
We multiply parentheses
6u-(-3u+27)+18=0
We get rid of parentheses
6u+3u-27+18=0
We add all the numbers together, and all the variables
9u-9=0
We move all terms containing u to the left, all other terms to the right
9u=9
u=9/9
u=1

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