6(u+3)=-3u+27

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Solution for 6(u+3)=-3u+27 equation: 



6(u+3)=-3u+27

We move all terms to the left:

6(u+3)-(-3u+27)=0

We multiply parentheses

6u-(-3u+27)+18=0

We get rid of parentheses

6u+3u-27+18=0

We add all the numbers together, and all the variables

9u-9=0

We move all terms containing u to the left, all other terms to the right

9u=9

u=9/9

u=1

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