6(u+3)=-4(4u-2)+6u

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Solution for 6(u+3)=-4(4u-2)+6u equation: 



6(u+3)=-4(4u-2)+6u

We move all terms to the left:

6(u+3)-(-4(4u-2)+6u)=0

We multiply parentheses

6u-(-4(4u-2)+6u)+18=0



We calculate terms in parentheses: -(-4(4u-2)+6u), so:

-4(4u-2)+6u

We add all the numbers together, and all the variables

6u-4(4u-2)

We multiply parentheses

6u-16u+8

We add all the numbers together, and all the variables

-10u+8

Back to the equation:

-(-10u+8)



We get rid of parentheses

6u+10u-8+18=0

We add all the numbers together, and all the variables

16u+10=0

We move all terms containing u to the left, all other terms to the right

16u=-10

u=-10/16

u=-5/8

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