6(u+3)=1

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Solution for 6(u+3)=1 equation: 



6(u+3)=1

We move all terms to the left:

6(u+3)-(1)=0

We multiply parentheses

6u+18-1=0

We add all the numbers together, and all the variables

6u+17=0

We move all terms containing u to the left, all other terms to the right

6u=-17

u=-17/6

u=-2+5/6

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