6(u+3)=3u+48

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Solution for 6(u+3)=3u+48 equation: 



6(u+3)=3u+48

We move all terms to the left:

6(u+3)-(3u+48)=0

We multiply parentheses

6u-(3u+48)+18=0

We get rid of parentheses

6u-3u-48+18=0

We add all the numbers together, and all the variables

3u-30=0

We move all terms containing u to the left, all other terms to the right

3u=30

u=30/3

u=10

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