6(u+3)=4u+14

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Solution for 6(u+3)=4u+14 equation: 



6(u+3)=4u+14

We move all terms to the left:

6(u+3)-(4u+14)=0

We multiply parentheses

6u-(4u+14)+18=0

We get rid of parentheses

6u-4u-14+18=0

We add all the numbers together, and all the variables

2u+4=0

We move all terms containing u to the left, all other terms to the right

2u=-4

u=-4/2

u=-2

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