6(u+5)=-5(2u-5)+6u

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Solution for 6(u+5)=-5(2u-5)+6u equation: 



6(u+5)=-5(2u-5)+6u

We move all terms to the left:

6(u+5)-(-5(2u-5)+6u)=0

We multiply parentheses

6u-(-5(2u-5)+6u)+30=0



We calculate terms in parentheses: -(-5(2u-5)+6u), so:

-5(2u-5)+6u

We add all the numbers together, and all the variables

6u-5(2u-5)

We multiply parentheses

6u-10u+25

We add all the numbers together, and all the variables

-4u+25

Back to the equation:

-(-4u+25)



We get rid of parentheses

6u+4u-25+30=0

We add all the numbers together, and all the variables

10u+5=0

We move all terms containing u to the left, all other terms to the right

10u=-5

u=-5/10

u=-1/2

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