6(u-1)=2u+4-5(-2u-1)

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Solution for 6(u-1)=2u+4-5(-2u-1) equation: 



6(u-1)=2u+4-5(-2u-1)

We move all terms to the left:

6(u-1)-(2u+4-5(-2u-1))=0

We multiply parentheses

6u-(2u+4-5(-2u-1))-6=0



We calculate terms in parentheses: -(2u+4-5(-2u-1)), so:

2u+4-5(-2u-1)

determiningTheFunctionDomain
2u-5(-2u-1)+4

We multiply parentheses

2u+10u+5+4

We add all the numbers together, and all the variables

12u+9

Back to the equation:

-(12u+9)



We get rid of parentheses

6u-12u-9-6=0

We add all the numbers together, and all the variables

-6u-15=0

We move all terms containing u to the left, all other terms to the right

-6u=15

u=15/-6

u=-2+1/2

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