6(u-1)=8u+5-2(-4u-2)

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Solution for 6(u-1)=8u+5-2(-4u-2) equation: 



6(u-1)=8u+5-2(-4u-2)

We move all terms to the left:

6(u-1)-(8u+5-2(-4u-2))=0

We multiply parentheses

6u-(8u+5-2(-4u-2))-6=0



We calculate terms in parentheses: -(8u+5-2(-4u-2)), so:

8u+5-2(-4u-2)

determiningTheFunctionDomain
8u-2(-4u-2)+5

We multiply parentheses

8u+8u+4+5

We add all the numbers together, and all the variables

16u+9

Back to the equation:

-(16u+9)



We get rid of parentheses

6u-16u-9-6=0

We add all the numbers together, and all the variables

-10u-15=0

We move all terms containing u to the left, all other terms to the right

-10u=15

u=15/-10

u=-1+1/2

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