6(u-2)+1=(3u-5)

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Solution for 6(u-2)+1=(3u-5) equation: 



6(u-2)+1=(3u-5)

We move all terms to the left:

6(u-2)+1-((3u-5))=0

We multiply parentheses

6u-((3u-5))-12+1=0



We calculate terms in parentheses: -((3u-5)), so:

(3u-5)

We get rid of parentheses

3u-5

Back to the equation:

-(3u-5)



We add all the numbers together, and all the variables

6u-(3u-5)-11=0

We get rid of parentheses

6u-3u+5-11=0

We add all the numbers together, and all the variables

3u-6=0

We move all terms containing u to the left, all other terms to the right

3u=6

u=6/3

u=2

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