6(u-2)+1=2(3u-5)

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Solution for 6(u-2)+1=2(3u-5) equation: 


Simplifying
6(u + -2) + 1 = 2(3u + -5)

Reorder the terms:
6(-2 + u) + 1 = 2(3u + -5)
(-2 * 6 + u * 6) + 1 = 2(3u + -5)
(-12 + 6u) + 1 = 2(3u + -5)

Reorder the terms:
-12 + 1 + 6u = 2(3u + -5)

Combine like terms: -12 + 1 = -11
-11 + 6u = 2(3u + -5)

Reorder the terms:
-11 + 6u = 2(-5 + 3u)
-11 + 6u = (-5 * 2 + 3u * 2)
-11 + 6u = (-10 + 6u)

Add '-6u' to each side of the equation.
-11 + 6u + -6u = -10 + 6u + -6u

Combine like terms: 6u + -6u = 0
-11 + 0 = -10 + 6u + -6u
-11 = -10 + 6u + -6u

Combine like terms: 6u + -6u = 0
-11 = -10 + 0
-11 = -10

Solving
-11 = -10

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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