6(u-2)+1=2(3v-5)

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Solution for 6(u-2)+1=2(3v-5) equation:


Simplifying
6(u + -2) + 1 = 2(3v + -5)

Reorder the terms:
6(-2 + u) + 1 = 2(3v + -5)
(-2 * 6 + u * 6) + 1 = 2(3v + -5)
(-12 + 6u) + 1 = 2(3v + -5)

Reorder the terms:
-12 + 1 + 6u = 2(3v + -5)

Combine like terms: -12 + 1 = -11
-11 + 6u = 2(3v + -5)

Reorder the terms:
-11 + 6u = 2(-5 + 3v)
-11 + 6u = (-5 * 2 + 3v * 2)
-11 + 6u = (-10 + 6v)

Solving
-11 + 6u = -10 + 6v

Solving for variable 'u'.

Move all terms containing u to the left, all other terms to the right.

Add '11' to each side of the equation.
-11 + 11 + 6u = -10 + 11 + 6v

Combine like terms: -11 + 11 = 0
0 + 6u = -10 + 11 + 6v
6u = -10 + 11 + 6v

Combine like terms: -10 + 11 = 1
6u = 1 + 6v

Divide each side by '6'.
u = 0.1666666667 + v

Simplifying
u = 0.1666666667 + v

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