6(u-2)+2=6(u-2)+2+u

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Solution for 6(u-2)+2=6(u-2)+2+u equation: 



6(u-2)+2=6(u-2)+2+u

We move all terms to the left:

6(u-2)+2-(6(u-2)+2+u)=0

We multiply parentheses

6u-(6(u-2)+2+u)-12+2=0



We calculate terms in parentheses: -(6(u-2)+2+u), so:

6(u-2)+2+u

determiningTheFunctionDomain
6(u-2)+u+2

We add all the numbers together, and all the variables

u+6(u-2)+2

We multiply parentheses

u+6u-12+2

We add all the numbers together, and all the variables

7u-10

Back to the equation:

-(7u-10)



We add all the numbers together, and all the variables

6u-(7u-10)-10=0

We get rid of parentheses

6u-7u+10-10=0

We add all the numbers together, and all the variables

-u=0

u=0/-1

u=0

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