6(u-2)+2=6(u-2)+2+u

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Solution for 6(u-2)+2=6(u-2)+2+u equation:



6(u-2)+2=6(u-2)+2+u
We move all terms to the left:
6(u-2)+2-(6(u-2)+2+u)=0
We multiply parentheses
6u-(6(u-2)+2+u)-12+2=0
We calculate terms in parentheses: -(6(u-2)+2+u), so:
6(u-2)+2+u
determiningTheFunctionDomain 6(u-2)+u+2
We add all the numbers together, and all the variables
u+6(u-2)+2
We multiply parentheses
u+6u-12+2
We add all the numbers together, and all the variables
7u-10
Back to the equation:
-(7u-10)
We add all the numbers together, and all the variables
6u-(7u-10)-10=0
We get rid of parentheses
6u-7u+10-10=0
We add all the numbers together, and all the variables
-u=0
u=0/-1
u=0

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