6(u-2)+2=6(u-2)+3+u

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Solution for 6(u-2)+2=6(u-2)+3+u equation: 



6(u-2)+2=6(u-2)+3+u

We move all terms to the left:

6(u-2)+2-(6(u-2)+3+u)=0

We multiply parentheses

6u-(6(u-2)+3+u)-12+2=0



We calculate terms in parentheses: -(6(u-2)+3+u), so:

6(u-2)+3+u

determiningTheFunctionDomain
6(u-2)+u+3

We add all the numbers together, and all the variables

u+6(u-2)+3

We multiply parentheses

u+6u-12+3

We add all the numbers together, and all the variables

7u-9

Back to the equation:

-(7u-9)



We add all the numbers together, and all the variables

6u-(7u-9)-10=0

We get rid of parentheses

6u-7u+9-10=0

We add all the numbers together, and all the variables

-1u-1=0

We move all terms containing u to the left, all other terms to the right

-u=1

u=1/-1

u=-1

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