6(u-2)+2=7u-12+2

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Solution for 6(u-2)+2=7u-12+2 equation:



6(u-2)+2=7u-12+2
We move all terms to the left:
6(u-2)+2-(7u-12+2)=0
We add all the numbers together, and all the variables
6(u-2)-(7u-10)+2=0
We multiply parentheses
6u-(7u-10)-12+2=0
We get rid of parentheses
6u-7u+10-12+2=0
We add all the numbers together, and all the variables
-u=0
u=0/-1
u=0

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