6(u-2)+2=7u-12+2

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Solution for 6(u-2)+2=7u-12+2 equation: 



6(u-2)+2=7u-12+2

We move all terms to the left:

6(u-2)+2-(7u-12+2)=0

We add all the numbers together, and all the variables

6(u-2)-(7u-10)+2=0

We multiply parentheses

6u-(7u-10)-12+2=0

We get rid of parentheses

6u-7u+10-12+2=0

We add all the numbers together, and all the variables

-u=0

u=0/-1

u=0

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