6(u-2)+2=u-1

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Solution for 6(u-2)+2=u-1 equation:



6(u-2)+2=u-1
We move all terms to the left:
6(u-2)+2-(u-1)=0
We multiply parentheses
6u-(u-1)-12+2=0
We get rid of parentheses
6u-u+1-12+2=0
We add all the numbers together, and all the variables
5u-9=0
We move all terms containing u to the left, all other terms to the right
5u=9
u=9/5
u=1+4/5

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