6(u-2)+2=u-1

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Solution for 6(u-2)+2=u-1 equation: 



6(u-2)+2=u-1

We move all terms to the left:

6(u-2)+2-(u-1)=0

We multiply parentheses

6u-(u-1)-12+2=0

We get rid of parentheses

6u-u+1-12+2=0

We add all the numbers together, and all the variables

5u-9=0

We move all terms containing u to the left, all other terms to the right

5u=9

u=9/5

u=1+4/5

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