6(u-3)-3=-2(-8u+9)-u

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Solution for 6(u-3)-3=-2(-8u+9)-u equation: 



6(u-3)-3=-2(-8u+9)-u

We move all terms to the left:

6(u-3)-3-(-2(-8u+9)-u)=0

We multiply parentheses

6u-(-2(-8u+9)-u)-18-3=0



We calculate terms in parentheses: -(-2(-8u+9)-u), so:

-2(-8u+9)-u

We add all the numbers together, and all the variables

-1u-2(-8u+9)

We multiply parentheses

-1u+16u-18

We add all the numbers together, and all the variables

15u-18

Back to the equation:

-(15u-18)



We add all the numbers together, and all the variables

6u-(15u-18)-21=0

We get rid of parentheses

6u-15u+18-21=0

We add all the numbers together, and all the variables

-9u-3=0

We move all terms containing u to the left, all other terms to the right

-9u=3

u=3/-9

u=-1/3

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