6(u-3)=2u-22

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Solution for 6(u-3)=2u-22 equation: 



6(u-3)=2u-22

We move all terms to the left:

6(u-3)-(2u-22)=0

We multiply parentheses

6u-(2u-22)-18=0

We get rid of parentheses

6u-2u+22-18=0

We add all the numbers together, and all the variables

4u+4=0

We move all terms containing u to the left, all other terms to the right

4u=-4

u=-4/4

u=-1

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