6(u-4)=-2u+48

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Solution for 6(u-4)=-2u+48 equation: 



6(u-4)=-2u+48

We move all terms to the left:

6(u-4)-(-2u+48)=0

We multiply parentheses

6u-(-2u+48)-24=0

We get rid of parentheses

6u+2u-48-24=0

We add all the numbers together, and all the variables

8u-72=0

We move all terms containing u to the left, all other terms to the right

8u=72

u=72/8

u=9

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