6(u-5)-3=-7(-3u+6)-9u

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Solution for 6(u-5)-3=-7(-3u+6)-9u equation: 



6(u-5)-3=-7(-3u+6)-9u

We move all terms to the left:

6(u-5)-3-(-7(-3u+6)-9u)=0

We multiply parentheses

6u-(-7(-3u+6)-9u)-30-3=0



We calculate terms in parentheses: -(-7(-3u+6)-9u), so:

-7(-3u+6)-9u

We add all the numbers together, and all the variables

-9u-7(-3u+6)

We multiply parentheses

-9u+21u-42

We add all the numbers together, and all the variables

12u-42

Back to the equation:

-(12u-42)



We add all the numbers together, and all the variables

6u-(12u-42)-33=0

We get rid of parentheses

6u-12u+42-33=0

We add all the numbers together, and all the variables

-6u+9=0

We move all terms containing u to the left, all other terms to the right

-6u=-9

u=-9/-6

u=1+1/2

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