6(v+)1=2(1-3v)-8

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Solution for 6(v+)1=2(1-3v)-8 equation: 



6(v+)1=2(1-3v)-8

We move all terms to the left:

6(v+)1-(2(1-3v)-8)=0

We add all the numbers together, and all the variables

6(+v)1-(2(-3v+1)-8)=0

We multiply parentheses

6v-(2(-3v+1)-8)=0



We calculate terms in parentheses: -(2(-3v+1)-8), so:

2(-3v+1)-8

We multiply parentheses

-6v+2-8

We add all the numbers together, and all the variables

-6v-6

Back to the equation:

-(-6v-6)



We get rid of parentheses

6v+6v+6=0

We add all the numbers together, and all the variables

12v+6=0

We move all terms containing v to the left, all other terms to the right

12v=-6

v=-6/12

v=-1/2

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