6(v+1)+8v=2(v-3)

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Solution for 6(v+1)+8v=2(v-3) equation: 



6(v+1)+8v=2(v-3)

We move all terms to the left:

6(v+1)+8v-(2(v-3))=0

We add all the numbers together, and all the variables

8v+6(v+1)-(2(v-3))=0

We multiply parentheses

8v+6v-(2(v-3))+6=0



We calculate terms in parentheses: -(2(v-3)), so:

2(v-3)

We multiply parentheses

2v-6

Back to the equation:

-(2v-6)



We add all the numbers together, and all the variables

14v-(2v-6)+6=0

We get rid of parentheses

14v-2v+6+6=0

We add all the numbers together, and all the variables

12v+12=0

We move all terms containing v to the left, all other terms to the right

12v=-12

v=-12/12

v=-1

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