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6(v+1)-9=4(v-1+2v
We move all terms to the left:
6(v+1)-9-(4(v-1+2v)=0
We add all the numbers together, and all the variables
6(v+1)-(4(3v-1)-9=0
We multiply parentheses
6v-(4(3v-1)-9+6=0
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