6(v+1)=2(1-3v)-8

Solution for 6(v+1)=2(1-3v)-8 equation:

6(v+1)=2(1-3v)-8

We move all terms to the left:

6(v+1)-(2(1-3v)-8)=0

We add all the numbers together, and all the variables

6(v+1)-(2(-3v+1)-8)=0

We multiply parentheses

6v-(2(-3v+1)-8)+6=0


We calculate terms in parentheses: -(2(-3v+1)-8), so:

2(-3v+1)-8

We multiply parentheses

-6v+2-8

We add all the numbers together, and all the variables

-6v-6

Back to the equation:

-(-6v-6)


We get rid of parentheses

6v+6v+6+6=0

We add all the numbers together, and all the variables

12v+12=0

We move all terms containing v to the left, all other terms to the right

12v=-12

v=-12/12

v=-1