6(v+2)+2v=28

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Solution for 6(v+2)+2v=28 equation: 



6(v+2)+2v=28

We move all terms to the left:

6(v+2)+2v-(28)=0

We add all the numbers together, and all the variables

2v+6(v+2)-28=0

We multiply parentheses

2v+6v+12-28=0

We add all the numbers together, and all the variables

8v-16=0

We move all terms containing v to the left, all other terms to the right

8v=16

v=16/8

v=2

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