6(v+2)-2v=2(2v+4)-13

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Solution for 6(v+2)-2v=2(2v+4)-13 equation: 



6(v+2)-2v=2(2v+4)-13

We move all terms to the left:

6(v+2)-2v-(2(2v+4)-13)=0

We add all the numbers together, and all the variables

-2v+6(v+2)-(2(2v+4)-13)=0

We multiply parentheses

-2v+6v-(2(2v+4)-13)+12=0



We calculate terms in parentheses: -(2(2v+4)-13), so:

2(2v+4)-13

We multiply parentheses

4v+8-13

We add all the numbers together, and all the variables

4v-5

Back to the equation:

-(4v-5)



We add all the numbers together, and all the variables

4v-(4v-5)+12=0

We get rid of parentheses

4v-4v+5+12=0

We add all the numbers together, and all the variables

17!=0

There is no solution for this equation

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