6(v+2)=-2v-20

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Solution for 6(v+2)=-2v-20 equation: 



6(v+2)=-2v-20

We move all terms to the left:

6(v+2)-(-2v-20)=0

We multiply parentheses

6v-(-2v-20)+12=0

We get rid of parentheses

6v+2v+20+12=0

We add all the numbers together, and all the variables

8v+32=0

We move all terms containing v to the left, all other terms to the right

8v=-32

v=-32/8

v=-4

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