6(v+3)-2v=2(2v+4)-10

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Solution for 6(v+3)-2v=2(2v+4)-10 equation: 



6(v+3)-2v=2(2v+4)-10

We move all terms to the left:

6(v+3)-2v-(2(2v+4)-10)=0

We add all the numbers together, and all the variables

-2v+6(v+3)-(2(2v+4)-10)=0

We multiply parentheses

-2v+6v-(2(2v+4)-10)+18=0



We calculate terms in parentheses: -(2(2v+4)-10), so:

2(2v+4)-10

We multiply parentheses

4v+8-10

We add all the numbers together, and all the variables

4v-2

Back to the equation:

-(4v-2)



We add all the numbers together, and all the variables

4v-(4v-2)+18=0

We get rid of parentheses

4v-4v+2+18=0

We add all the numbers together, and all the variables

20!=0

There is no solution for this equation

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