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6(v+3)-2v=2(2v+4)-17
We move all terms to the left:
6(v+3)-2v-(2(2v+4)-17)=0
We add all the numbers together, and all the variables
-2v+6(v+3)-(2(2v+4)-17)=0
We multiply parentheses
-2v+6v-(2(2v+4)-17)+18=0
We calculate terms in parentheses: -(2(2v+4)-17), so:We add all the numbers together, and all the variables
2(2v+4)-17
We multiply parentheses
4v+8-17
We add all the numbers together, and all the variables
4v-9
Back to the equation:
-(4v-9)
4v-(4v-9)+18=0
We get rid of parentheses
4v-4v+9+18=0
We add all the numbers together, and all the variables
27!=0
There is no solution for this equation
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