6(v+3)=-2(7v-3)+2v

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Solution for 6(v+3)=-2(7v-3)+2v equation: 



6(v+3)=-2(7v-3)+2v

We move all terms to the left:

6(v+3)-(-2(7v-3)+2v)=0

We multiply parentheses

6v-(-2(7v-3)+2v)+18=0



We calculate terms in parentheses: -(-2(7v-3)+2v), so:

-2(7v-3)+2v

We add all the numbers together, and all the variables

2v-2(7v-3)

We multiply parentheses

2v-14v+6

We add all the numbers together, and all the variables

-12v+6

Back to the equation:

-(-12v+6)



We get rid of parentheses

6v+12v-6+18=0

We add all the numbers together, and all the variables

18v+12=0

We move all terms containing v to the left, all other terms to the right

18v=-12

v=-12/18

v=-2/3

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